👍 Correct answer to the question Which property was used to write the equation in step 2? Step 1: 5(x-7)= 55 Step 2: 5x-35=55 Step 3 5x=90 Step 4 X= 18 A.In the step (2) reaction 90 % yield of H3PO4 is obtained. 1) P4 + 5O2 ? P4O10 2) P4O10 + 6H2O ? 4H3PO4 We allow 62 g of phosphorus to react with excess oxygen which from P4O10 in 85 % yield. Phosphoric acid (H3PO4) prepared in a two step process.With these forms, students write their names on their answer documents and when you scan, students names (a screenshot of their handwritten name) will. Then, click the green 20 question PDF button. However, if you choose to use the 20 question answer sheets, click the 'Answer Sheets' tab located at the top of your online ZipGrade account page.
